Solve the following system of equations and show all of your work. 2x + 5y = −3 −15x − 5y = −10
need help please : (
2x + 5y = −3 −15x − 5y = −10 Let's use addition on this. -13x +0y = -13 -13x = - 13 x = 1
To get y, pick either equation and substitute 1 for x and then get y. 2x + 5y = −3 2(1) + 5y = -3 2 + 5y = -3 5y = -3 -2 5y = -5 y = -1 Solution (1, -1)
this is a system by elimination because in the 1rt question I have to choose
Part 1: Decide whether you would use the graphing, substitution, or elimination method to solve the following system of equations. Explain, in complete sentences, why you chose that method.
Is this a new question or does it go with the first problem?
can you help me whit this one because I chose substitution and now I'm not sure
is same question
it goes with the first problem
are u confuse
???
You can use any of those methods to solve the system. When you used substitution, did you get the correct answer?
Do you want me to explain in sentences why I chose the elimination technique?
yes please but I dont have to chose one of this method to graph
I looked at the two equations 2x + 5y = −3 and −15x − 5y = −10 and saw that the y terms were additive inverses and would add to 0 and eliminate the y-variable. With the y-variable gone, I would be left with one equation in one unknown which I could solve. That is -13x +0y = -13 which has an answer of x = 1.
oh ok get you now make sense now =) thank you
Then, I had to find y by substituting 1 for x in one of the two given equations. I chose the first one. 2x + 5y = −3 and got -1 for y. See below. 2(1) + 5y = -3 2 + 5y = -3 5y = -3 -2 5y = -5 y = -1 So, the solution for the system is (1,-1).
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