Question

Can someone please explain how to solve this: Solve x2 + 4x + 8 = 0

Answer 1

Is x2 suppose to be 2x or \[x ^{2}\]

Answer 2

If so, what adds to 8 and multiplies to 4?

Answer 3

Quadratic equation my friend, you'll have two complex numbers

Answer 4

Or is it the other way around...

Answer 5

You can use the quadratic formula:
\[x=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \]

Answer 6

Or complete the square.

Answer 7

Its x^2

Answer 8

mimi which was is easier

Answer 9

It depends on you; but I think the quadratic formula is easier. Since you will have complex numbers as the answer.

Answer 10

The discrimant, b^2-4ac=-16, so you'll have 2 complex numbers

Answer 11

Which numbers are A B and C in the equation

Answer 12

ax^2+bx+c=0

Answer 13

a=1
b=4
c=8