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Suppose for this problem that Pr[E]=19/24and Pr[F]=13/24 Pr[(E∪F)']=0 (1) What is Pr[E|F]? (2) What is Pr[F|E]?
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use... if Pr[(E∪F)']=0 then Pr[E∪F]=1 \[Pr[E|F]=Pr[E\cap F]/Pr[F]\] \[1=Pr(E\cup F)=Pr(E)+Pr(F)-Pr[E\cap F]\]
I've never done this stuff before, but following Zarkon's tip\[Pr[E\cap F]=Pr(E)+Pr(F)-Pr[E\cup F]\]\[Pr[E|F]=\frac{Pr(E)+Pr(F)-Pr[E\cup F]}{Pr[F]}\]and extrapolating for the other one\[Pr[F|E]=\frac{Pr[E\cap F]}{Pr[E]}=\frac{Pr(E)+Pr(F)-Pr[E\cup F]}{Pr[E]}\]
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