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Mathematics 16 Online
OpenStudy (anonymous):

What formula is used to find the rate of change if data is given?

OpenStudy (anonymous):

average rate of change?

OpenStudy (anonymous):

dy/dx

OpenStudy (anonymous):

yes that would work for instantaneous change, for average change you could use the difference quotient

OpenStudy (anonymous):

\[\frac{f(x+h)-f(x)}{h}\]

OpenStudy (anonymous):

Thanks @rickjbr

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

We'd need a regression to find dy/dx using only data. For everything else there's mastercard, I mean, average change.

OpenStudy (anonymous):

So just to clarify on the formula above where would i plug in the data? Sorry to bug = [

OpenStudy (anonymous):

lets say I had the points (1,3) and (2,5) for my data. The slope would be (5-3)/(2-1), where (2-1)=h, and 5=f(x+h), and 3=f(x)

OpenStudy (anonymous):

So the slope would be 2/1? Right?

OpenStudy (anonymous):

in that example, yes

OpenStudy (anonymous):

For the example I gave? Yeah.

OpenStudy (anonymous):

sweet! so where would i get my y intercept to create the y=mx+b?

OpenStudy (anonymous):

i know that x = 2/1 but b?

OpenStudy (anonymous):

i meant i know that 2 = m

OpenStudy (anonymous):

If you have a datapoint (x,y), you can just plug in x and y in y=mx+b, where we know m from the previous example. So solve for b, and you're set!

OpenStudy (anonymous):

solve for b by plugging results into point slope formula?

OpenStudy (anonymous):

Yeah.

OpenStudy (anonymous):

is the answer \[y=2x-5\]?

OpenStudy (anonymous):

No, unless I'm doing something wrong, it should be y=2x+1.

OpenStudy (anonymous):

i'm wrong...

OpenStudy (anonymous):

you're wrong?

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