NOTE: A<2, 3, 6> and B<1, -1, 7> Find the point of intersection of the diagonals of the parallelogram generated by OAand OB. (the three vertices of the parallelogram would be (0,0,0), (2,3, 6), and (1, -1, 7))
That's in three dimensions? The fourth vertex of the parallelogram C would be O + A-B = A-B, or (1,4,-1). So your diagonals would be the line segments OA and BC. You could then get the equations for those two lines, which should help you find their intersection point.
yah its 3d
I do not understand the meaning of OA and OB
OA and OB are two edges of the parallelogram starting at point O and going to point A and B, respectively. Basically, the two give you one half of the parallelogram - but since opposite sides are parallel, you can easily reconstruct the missing vertex (which is what I did above to get C). O is the origin, or (0,0,0).
How is that a missing vertex when its given?
nvm i see what you said with C give me a second
ok well I dont know where to start
No wait - that's wrong hold on
ok
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