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Mathematics 8 Online
OpenStudy (anonymous):

NOTE: A<2, 3, 6> and B<1, -1, 7> Find the point of intersection of the diagonals of the parallelogram generated by OAand OB. (the three vertices of the parallelogram would be (0,0,0), (2,3, 6), and (1, -1, 7))

OpenStudy (anonymous):

That's in three dimensions? The fourth vertex of the parallelogram C would be O + A-B = A-B, or (1,4,-1). So your diagonals would be the line segments OA and BC. You could then get the equations for those two lines, which should help you find their intersection point.

OpenStudy (anonymous):

yah its 3d

OpenStudy (anonymous):

I do not understand the meaning of OA and OB

OpenStudy (anonymous):

OA and OB are two edges of the parallelogram starting at point O and going to point A and B, respectively. Basically, the two give you one half of the parallelogram - but since opposite sides are parallel, you can easily reconstruct the missing vertex (which is what I did above to get C). O is the origin, or (0,0,0).

OpenStudy (anonymous):

How is that a missing vertex when its given?

OpenStudy (anonymous):

nvm i see what you said with C give me a second

OpenStudy (anonymous):

ok well I dont know where to start

OpenStudy (anonymous):

No wait - that's wrong hold on

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Like this: |dw:1329123849205:dw|

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