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Mathematics 18 Online
OpenStudy (anonymous):

Why isn't the answer 3 or -3?

OpenStudy (anonymous):

OpenStudy (anonymous):

l 3(0+h) l - l 3(0) l / h = l 3h l / h is what i have...

OpenStudy (radar):

The answer is -3 because (-2)^3=-8 (-2 x-2 x-2)=-8

OpenStudy (radar):

and of course 24/-8=-3

OpenStudy (anonymous):

its NOT -3 ...like i said

OpenStudy (radar):

I was looking at the other document lol with the problem:\[(-m)^{-3}n\] if m=2 ,n=24

OpenStudy (anonymous):

\[\lim_{h \rightarrow 0+} \frac{3\left| h \right|}{h}=\lim_{h \rightarrow 0+} \frac{3h}{h}=3\] \[\lim_{h \rightarrow 0-} \frac{3\left| h \right|}{h}=\lim_{h \rightarrow 0-}\frac{3(-h)}{h}=-3\]

OpenStudy (anonymous):

The limit doesn't exist at 0

OpenStudy (anonymous):

the acceptable answer on my hw site is DNE (Does Not Exist)

OpenStudy (anonymous):

thanks for helping

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

you see why though?

OpenStudy (anonymous):

there are 2 answers that are both positive and negative coming from opposite directions???

OpenStudy (anonymous):

it comes from the definition of absolute value

OpenStudy (anonymous):

if x>0, |x|=x if x<0, |x|=-x

OpenStudy (anonymous):

That's what i showed up above with the left and right limits

OpenStudy (anonymous):

so any time i have an absolute value the limit will not exist?

OpenStudy (anonymous):

don't assume that...it would exist if the function were continuous at the x-value of the limit you were looking for. If h->1, the limit would exist

OpenStudy (anonymous):

ok ok

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