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prove or disprove: If a divides bc, then a divides b or a divides c
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let b=3, c=4, a=6
-sigh here is a variable-based counterexample. (Clearly, a must be greater than 1 since otherwise it is true! 1 divides every integer.) Let b = a+1 and c = a-1 Then, b+c = 2a Obviously a divides b+c since a divides 2a. But since a>1, a cannot divide b since b ≡ 1 (mod a) and a cannot divide c since c ≡ -1 (mod a)
got it?
yeah, i think so. thanks.
to disprove a statement, all you need is one counter-example.
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