Solve the equation and check for extraneous solutions. Click to see question!
\[\sqrt{7x+2}-2=7x\]
\[\sqrt{7x+2} = 7x + 2\]
so what must 7x+ 2 be?
Huuhh?
Is that the answer?
what number is square root of itself?
1 right?
I'm so bad at math and I have no idea what your talking about.
7x + 2 = 1 7x = -1 x = -1/7
Your sure that's right?
yea = try plugging in x = -1/7 in the original equation: left hand side of equation: sqrt ( 7 * -1/7 + 2) - 2 = sqrt(-1+2) - 2 = sqrt1 - 2 = -1 right hand side: 7*-1/7 + 2 = 1 - no thats not right
So what's the answer? haha.
Add 2 to both sides, square both sides, solve for x. Check your solutions in the original formula. One of them probably won't work
7x+2=(7x+2)^2 7x+2=49x^2+28x+4 49x^2+21x+2=0
Use quadratic formula, you'll get 2 answers. Check them both in the original equation and see which one works.
my concentration is poor today
49x^2+21x+2=0 SO this is the answer?
oh hold - -1/7 is a solution - i made a mistake when i checked it rhs = -1
That's not the answer. Use the quadratic formula to get the answers from there.
Can you please just give me the answer I'm so bad at this and this is my last question!
yes -1/7 is correct
check back - i made a mistake right hand side = 7 * -1/7 = -1
yes it works in original equation
Which one is the answer?!
-1/7 is correct
Yes, i double checked, there are 2 answers here...
-1/7 and -2/7 work, which you'd get from the quadratic formula
Join our real-time social learning platform and learn together with your friends!