Question

solve 2x^2 + 7x + 3=0 solve using the quadratic formula

Answer 1

simple:

Answer 2

resolvent formula

Answer 3

x=-0.5
x=-3

Answer 4

understand?

Answer 5

know resolvent form?

Answer 6

i just attached the answer. :-)

Answer 7

Using the quadratic formula,
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
\[x=\frac{-7 \pm \sqrt{7^2-4(2)(3)}}{2(2)}\]
\[x=\frac{-7 \pm \sqrt{25}}{4}=\frac{-7 \pm 5}{4}=-\frac{1}{2}, -3\]

Answer 8

You can also factor this using the grouping method:
2x^2+7x+3=0
2x^2+6x+x+3=0
2x(x+3)+(x+3)=0
(x+3)(2x+1)=0
x=-3, -1/2