the lengths of two diagonals of a particular rhombus are 10 ft and 14 ft, what is the perimter of the rhombus?

Question

anonymous · Answer

since diagonals of a rhombus bisect each other at right angles, so thie halves form a right angled triangle with the side being the hypotenuse|dw:1329255947123:dw|

anonymous · Answer

so 
side^2 = 7^2 + 5^2
side^2  = 49 + 25 = 74
so side = sqroot(74) = 8.6 ft approx

anonymous · Answer

That's what I was getting, but I wasnt sure if 8.6 was the right answer. Didn't know if it had to be a whole number or not.

anonymous · Answer

do you multiply 8.6 times 4 because it's a rhombus?

anonymous · Answer

yes perimeter will be = 4*side
if u want more exact answer, then perimeter = 4*sqroot(74) = $$4\sqrt{74}$$

anonymous · Answer

Thank you!