Question

the lengths of two diagonals of a particular rhombus are 10 ft and 14 ft, what is the perimter of the rhombus?

Answer 1

since diagonals of a rhombus bisect each other at right angles, so thie halves form a right angled triangle with the side being the hypotenuse

Answer 2

so
side^2 = 7^2 + 5^2
side^2 = 49 + 25 = 74
so side = sqroot(74) = 8.6 ft approx

Answer 3

That's what I was getting, but I wasnt sure if 8.6 was the right answer. Didn't know if it had to be a whole number or not.

Answer 4

do you multiply 8.6 times 4 because it's a rhombus?

Answer 5

yes perimeter will be = 4*side
if u want more exact answer, then perimeter = 4*sqroot(74) = \[4\sqrt{74}\]

Answer 6

Thank you!