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Mathematics 15 Online
OpenStudy (anonymous):

simplify b-3/b^2-6b+9

OpenStudy (anonymous):

answer is -5b^3+9b^2-3

OpenStudy (saifoo.khan):

Are u sure?

OpenStudy (anonymous):

yes - basically combine like terms b-6b and then I multiplied by b^2 to get rid of the fraction - rewrite to start with highest power down

OpenStudy (anonymous):

that doesn't look correct

OpenStudy (saifoo.khan):

\[\frac{b-3}{b^2-6b+9}\]That's this @Juanita.

OpenStudy (anonymous):

1/b-3

OpenStudy (anonymous):

i read the problem as if she meant b/3 - in the future - please put parenthesis around numerators and denominators -

OpenStudy (anonymous):

yes daydream is correct since saifoo rewrote the problem

OpenStudy (anonymous):

|dw:1329261403931:dw|

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