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simplify b-3/b^2-6b+9
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answer is -5b^3+9b^2-3
Are u sure?
yes - basically combine like terms b-6b and then I multiplied by b^2 to get rid of the fraction - rewrite to start with highest power down
that doesn't look correct
\[\frac{b-3}{b^2-6b+9}\]That's this @Juanita.
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1/b-3
i read the problem as if she meant b/3 - in the future - please put parenthesis around numerators and denominators -
yes daydream is correct since saifoo rewrote the problem
|dw:1329261403931:dw|
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