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I can't remember the steps to do this problem: (-4x)^2(3x^8)^2
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PEMDAS is needed here. So, first, square the terms in the parenthesis.
What do you get?
-16x and 9x^8?
square the entire term (-4x) and you get....
\[\Large (-4x)(-4x) \times (3x^8)(3x^8)\] Can u solve now?
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Ah! Lemme give it a shot!
16x * 9x^16?
Almost. What is x*x?
1?
Same rule as when you did (x^8) * (x^8)
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So the answer is 144x^8 ?
Sorry, 144x^16
144x^18
How do you get 18 as an exponent?
I am sure u missed to add the "left exponents"
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(-4x)(-4x) -4 * - 4 = 16 x * x = x^2
Oh! Yes I did miss that part! I see now and thank you all so very much :)
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