Question

Hello, I'm trying to understand d/dx(2/sqrt(x)) please help.

Answer 1

\[so, d/dx \left[ 2/\sqrt{x} \right]\]

Answer 2

= 2 d/dx [x^(-1/2)]
= 2(- 1/2)[ x^(-1/2 -1)]
=- x^(-3/2)

Answer 3

Thank you! I've posted one more question about the same subject.