Question

Solve the system.
y = -1/3 x + 2 and x + 3y = 3

(0, 1)
(1, 0)
(3, 1/3)
(3/2, 0)
no solution

The ordered pair (-1, -1) is a solution of the system -4x + 2y = 2 and x + y = -2. (Points : 1)
True
False

How many solutions exist for the system y = 2x + 5 and y = -0.2x - 4? (Points : 1)
no solution
one solution
infinitely many solutions

How many solutions exist for the system, x + y = 1 and y = -x + 1? (Points : 1)
no solution
one solution
infinitely many solutions

Answer 1

Last questions please thank you!

Answer 2

FIRST QUESTION:
y = -1/3 x + 2 and x + 3y = 3

multiply the first equation by 3

3y = -x +2

so x+3y = 2
x+3y = 3

no solution (this is parallel)

SECOND QUESTION:
substitute the ordered pair to both equations...if the coordinates are correct when substituted, then they are the ones.

THIRD QUESTION:
Use discriminant(b^2 -4ac)

FOURTH QUESTION:
same with third