Suppose f(x) = x^2 - 3 x - 1.
Find the following information for this function.
The coordinates of the vertex are?
This parabola is what? concave up,down or both or neither
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OpenStudy (anonymous):
vertex ( 3/2, -1)
concave up - remember that F(x)= ax^2 + bx + c. concave direction is based on the sign of A - if negative: concave down and if positive : concave up
OpenStudy (anonymous):
the y intercepts occur at?
OpenStudy (anonymous):
FIND THE axis of symmetry by x = -b/2a
vertex is -b/2a, f(-b/2a)
OpenStudy (anonymous):
wait I now its a parabola and it contains a minimum but how do I find that?
OpenStudy (anonymous):
min is calculatd by y >= f(-b/2a)
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OpenStudy (anonymous):
ok so what is b and a?
OpenStudy (anonymous):
3/2 and -1?
OpenStudy (anonymous):
F(x)= ax^2 + bx + c standard
f(x) = x^2 - 3 x - 1 your problem
so a = 1
b = -3
c = -1
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
quadratic equation right?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
my son is learning this now and i just taught him - that is why i can answer so quick