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derivative of e^x - sin(y)=x
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e^x-1=cosy.(dy/dx)
if y is constant, the answer is e^x-1=0 and e^x=1 so x=0
no you can't solve for y easily so you have to use the thing with the y' ( i can't remember the name)
\[y=\sin^{-1} (e^x-x)\]
no 2 but i think thats right
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ok then arcsin(e^x-x)=y
so we take its derivative;
e^x-1/(1-[(e^x-x)^2]=dy/dx
\[\frac{d}{dx}\sin^{-1} x=\frac{1}{\sqrt{1-x^2}}\]
that's right..
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there is no sqrt in your solution..
\[\frac{e^x-1}{\sqrt{1-(e^x-x)^2}}\]
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