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integrate: (x-1)/(x^2 + 1) I recognize the denominator as arctan but not sure what that gets me?
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1/2 ln(x^2+1) - arctan(x)
You can break it up: \[\large \int\limits\frac{x-1}{x^{2}+1} dx = \int\limits\frac{x}{x^{2}+1} dx -\int\limits\frac{1}{x^{2}+1} dx\] The integrate it one by one.
The first one is a u sub & the next one is a trig inverse.
I was trying to make it way harder than that lol...dangit
Do you want to do it a hard way? lol
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