What is the slant asymptote for x^2/(x-9) ??
umm r u referring to the vertical and horizontal asymptote?
It's not x+9? slant/oblique
lol never heard of these terms :)
wt do u mean by not x+9
The answer is not x_9
x+9*
The slant or oblique asymptote has equation y = x + 9. Divide (x-9) into (x^2 +0x+0) and see the quotient "on top only" of x + 9. There are more sophisticated ways to obtain the equation. Regardless, there's good reading on finding equations of slant asymptotes at the link: http://www.purplemath.com/modules/asymnote.htm If the degree is higher on top, then the division gives a polynomial whose degree is the difference between the degrees of the numerator and denominator. Since you'll only be doing rationals where the numerator's degree is at most 1 greater than the denominator's degree, then the division will only give you, at most, a linear (straight-line) expression. For instance, ... continued at the link.
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