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Mathematics 16 Online
OpenStudy (anonymous):

What is the slant asymptote for x^2/(x-9) ??

OpenStudy (anonymous):

umm r u referring to the vertical and horizontal asymptote?

OpenStudy (anonymous):

It's not x+9? slant/oblique

OpenStudy (anonymous):

lol never heard of these terms :)

OpenStudy (anonymous):

wt do u mean by not x+9

OpenStudy (anonymous):

The answer is not x_9

OpenStudy (anonymous):

x+9*

Directrix (directrix):

The slant or oblique asymptote has equation y = x + 9. Divide (x-9) into (x^2 +0x+0) and see the quotient "on top only" of x + 9. There are more sophisticated ways to obtain the equation. Regardless, there's good reading on finding equations of slant asymptotes at the link: http://www.purplemath.com/modules/asymnote.htm If the degree is higher on top, then the division gives a polynomial whose degree is the difference between the degrees of the numerator and denominator. Since you'll only be doing rationals where the numerator's degree is at most 1 greater than the denominator's degree, then the division will only give you, at most, a linear (straight-line) expression. For instance, ... continued at the link.

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