Please answer drawing
|dw:1329313311587:dw| plot the point -63.4 I git -63.4 after finding tan inverse of (-2)
This... makes no sense to me. Am I being obtuse, or...?
-63.4degrees sorry
Oh, ok. |dw:1329313618900:dw| Angle n is -63.4 degrees, a is 2, and b is 1. Do you understand why?
No boss
arctan(a/b)=n-->tan(n)=a/b; does this make it any clearer?
Ok i think um near getting it.But tan=opposite/adjacent.Thefore n=tan inverse of 2/1=63.4.i guess its a negative because we are reading the angle anticlockwice.
Yup, or think of the -2 as a j-hat vector, so that its length-magnitude is 2, despite being written as -2.
wats a j-hat vector?
It's the y-component of a Euclidian vector. Don't worry about it if you haven't heard of it before.
Just think of it as -2 because it's extending in the negative direction.
ok :) and also boss i thought that the region where you plot the -63.4 degree angle is supposed to b where positive tan angles are to be plot|dw:1329314464862:dw| how come we plotted it there ?
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