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Mathematics 19 Online
OpenStudy (anonymous):

Please answer drawing

OpenStudy (anonymous):

|dw:1329313311587:dw| plot the point -63.4 I git -63.4 after finding tan inverse of (-2)

OpenStudy (anonymous):

This... makes no sense to me. Am I being obtuse, or...?

OpenStudy (anonymous):

-63.4degrees sorry

OpenStudy (anonymous):

Oh, ok. |dw:1329313618900:dw| Angle n is -63.4 degrees, a is 2, and b is 1. Do you understand why?

OpenStudy (anonymous):

No boss

OpenStudy (anonymous):

arctan(a/b)=n-->tan(n)=a/b; does this make it any clearer?

OpenStudy (anonymous):

Ok i think um near getting it.But tan=opposite/adjacent.Thefore n=tan inverse of 2/1=63.4.i guess its a negative because we are reading the angle anticlockwice.

OpenStudy (anonymous):

Yup, or think of the -2 as a j-hat vector, so that its length-magnitude is 2, despite being written as -2.

OpenStudy (anonymous):

wats a j-hat vector?

OpenStudy (anonymous):

It's the y-component of a Euclidian vector. Don't worry about it if you haven't heard of it before.

OpenStudy (anonymous):

Just think of it as -2 because it's extending in the negative direction.

OpenStudy (anonymous):

ok :) and also boss i thought that the region where you plot the -63.4 degree angle is supposed to b where positive tan angles are to be plot|dw:1329314464862:dw| how come we plotted it there ?

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