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solve the integral x/(3x+5)
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Use a substitution \(u=3x+5\), this is one way.
wont work !!!
you will still have x's left ...
solve for x
what do you mean solve for x ?
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\[u=3x+5 \implies x=\frac{1}{3}(u-5) \implies dx=\frac{1}{3}du.\]
mr math is writing it now i am sure, but solve \[u=3x+5\] for x
and then ? i tried polynomil division but couldn't do it ...
Using the substitution, your integration becomes: \[\frac{1}{9}\int \frac{u-5}{u}du.\] But \(\frac{u-5}{u}=1-\frac{5}{u}\). You should be able to take it from here.
Is that good enough?
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thank you !!! =]
Glad to help :-)
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