Question

Geometry Problem: I am given a right triangle with the 2 legs labeled x and the hypotenuse labeled h How do i solve for the value of h and i have to use an algebraic expression in terms of x ?

Answer 1

\[h=\sqrt{x ^{2}+x ^{2}}\]
h=\[h=\sqrt{2x ^{2}}\]
\[h=\sqrt{2}x\]

Answer 2

ok thank you

Answer 3

can you show me how to do this one and i got x but can u tell me if thats right or not

Answer 4

one leg is x and the other is h and the hypotenuse is 2x and i have to solve for h and i got just x did i do this right?

Answer 5

\[2x=\sqrt{x ^{2}+h ^{2}}\]
\[4x ^{2}=x ^{2}+h ^{2}\]
\[3x ^{2}=h ^{2}\]
\[\sqrt{3}x=h\]