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given sec (theta) = 3 what is the exact value of csc (90 - (theta))
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csc(90-theta) = sec (theta). The answer is 3.
how could you explain this in details please because this makes no sense
The "co" functions are shifts of the original functions by 90 degrees. So anytime you have any trigonometric function in which the argument is (90-theta), it is equal to the cofunction. For example, sin(90-theta)= cos (theta) cos(90-theta) = sin (theta) And so on for the other 4.
http://www.mathwords.com/c/cofunction_identities.htm A little better explanation.
your explanation was better thanks however how do you go about solving it .. like i know its a complementary and stuff but whats the first step how do you go from their??
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