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Indicate the equation of the given line in standard form. The line through (2, -1) and parallel to a line with slope of 3/4
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y + 1 = 3/4 (x - 2)
y = 3/4x - 3/2 -2/2 y = 3/4x -5/2
You can use point-slope form here: \[(y - y _{1}) = m (x - x _{1})\] Substitute your slope into m. And your y-coordinate for y1 and your x-coordinate for x1. Then solve for y.
_ x _ _ y _ _ _ thats how i have to put it in
Using point slope the equation looks like this: y + 1 = 3/4 (x - 2) y + 1 = 3/4x - 6/4 y = 3/4 x - 6/4 - 4/4 y = 3/4 x - 5/2
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