Write the simplest polynomial function with the given roots: 2i, sqrt(3), 4. I have gathered that a complex conjugate is needed for 2i, i.e. (x+2i)(x-2i) and the 4 translates into (x-4). Does the sqrt(3) need one or two binomials?

Question

lgbasallote · Answer

if x = 2i...then x = sqrt -2
x^2 = -2
first root is (x^2 +2) then (x^2-3) and x-4

lgbasallote · Answer

so your polynomial is (x^2+2)(x^2-3)(x-4) did you get that?

lgbasallote · Answer

oh wait sorry... x= sqrt -4
so it's (x^2 +4)

accessdenied · Answer

You also have to use the conjugate of the sqrt(3).  (I think it's the irrational root theorem?)

anonymous · Answer

Yes, thank you!.