how would I graph this? The C-intercept (y) is 6250 and the slope is 250. So mark a point on the C-axis that is 6 marks + 1/4 mark (6250). That is the y-intercept. Then use the slope to get to another point. Even though the slope is 250, you can rise 1000 and run 4 (1000/4 = 250).

Question

anonymous · Answer

Honestly, I can't understand what you just wrote.

anonymous · Answer

The C-axis is the y-axis? Then the y-intercept is 6250=b. The slope is 250; so y=250x+6250.

Graphing is about choosing a good scale.

anonymous · Answer

the question is this....

The sugar sweet company is going to transport its sugar to market. It will cost $6250.00 to rent trucks, and it will cost an additional $250.00 for each ton of sugar transported. Let C represent the total cost (in dollars), and let S represent the amount of sugar (in tons) transported. Write an equation relating C to S, and then graph your equation.

I have the equation i just dont know how to graph it?

anonymous · Answer

i have the y axis going by 1000's up to 9000 and x axis by one up to 8

anonymous · Answer

That seems sufficient.

anonymous · Answer

i just dont know how to graph it now lol! im stuck

anonymous · Answer

Mark the y-intercept on the y-axis... note your slope of 250... draw a line through the y-intercept that's slanted up above 45 degrees, assuming your x-axis goes up to 8.

anonymous · Answer

how would it look, can you draw it...

anonymous · Answer

so far i have...

anonymous · Answer

|dw:1329362256993:dw|
I'm not worried about scale; by marking the line's slope, the y-intercept, and such I can readjust the scales of the axes to fit the line.

anonymous · Answer

|dw:1329362215286:dw|

idk if that is any right

anonymous · Answer

The line is AT its y-intercept at x=0.