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Mathematics 23 Online
OpenStudy (anonymous):

I have an annoying question if anyone wants to help

OpenStudy (anonymous):

OpenStudy (anonymous):

no matter how boring

OpenStudy (anonymous):

what's antidifferentiate

razor99 (razor99):

u were right pipa borrrrrrrrriiiiiinnngggggg

OpenStudy (barrycarter):

You can generate the series for 1/(1-x^2) by replacing 'x' with 'x^2' on both sides of the power series for 1/(1-x): http://www.wolframalpha.com/input/?i=1%2F%281-x^2%29+power+series For 1/(1+x^2), start with 1/(1-x) and replace x with minus x to get the power series for 1/(1+x): http://www.wolframalpha.com/input/?i=1%2F%281%2Bx%29+power+series Then replace x with x^2 to get the power series for 1/(1+x^2): http://www.wolframalpha.com/input/?i=1%2F%281%2Bx^2%29+power+series Now, take that series and integrate term by term.

OpenStudy (pokemon23):

that's math

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