Heyy! Could someone help me with this? I don't understand how to do it. Thank youuu :)

If the dimensions of triangle RAH are twice as large as the corresponding dimensions of triangle EAC, calculate the length of sides RH and AH. Then explain if triangle RAH is similar to triangle EAC.

http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-WA10/b/assessments/S-SimilarityPostulatesQuiz/Geometry_6.2.14_Quiz_FINAL_3q6.gif

Question

Heyy! Could someone help me with this? I don't understand how to do it. Thank youuu :) 

If the dimensions of triangle RAH are twice as large as the corresponding dimensions of triangle EAC, calculate the length of sides RH and AH. Then explain if triangle RAH is similar to triangle EAC.

http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-WA10/b/assessments/S-SimilarityPostulatesQuiz/Geometry_6.2.14_Quiz_FINAL_3q6.gif

anonymous · Answer

I can do the last part but I don't know how to do the first part :(

razor99 · Answer

its a rigt triangle

directrix · Answer

AC/AH = 1/2

6/AH = 1/2

AH = 12

razor99 · Answer

hello u there

directrix · Answer

(EC) ^2 = (3.5)^2 + 6^2

Solve for EC.

Then, EC/RH = 1/2 

That's the plan so...

anonymous · Answer

Okay, that makes sense! Thank you! :) I can't believe I didn't get that!

directrix · Answer

EH = 6.95

6.95/RH = 1/2

RH = 13.9 approx

razor99 · Answer

Good work Directrix yaaaaaaaa