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given sin theta= -1/3 and sec theta > 0, find cos theta and tan theta
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sin^2 + cos^2 = 1 1/9 + cos^2 = 1 cos^2 = 1 - 1/9 cos = sqrt(8/9) = 2sqrt(2)/9
tan = sin/cos
since sin is - thats either in q3 or q4
sec is cos is + in q4
so tan is - in q4 :)
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so what does cos theta and tan theta equal?
i gave cos; and tan, for this case, is -sin/cos
|dw:1329402824401:dw|
tan is negative so that might be a bit misleading tan = - |sin/cos| might be a better representation
the answer include numers, though. like cos theta = - 2 the sqaure root of 2 and tan = 1/ 2 the square root of 2
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the numbers are what you get when you actually take the time to do the calculations.
cos was calculated for you; so take the initiative to determine the tan :)
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