Question

integration!!
(y^2)/(4-y^4)

Answer 1

\[(y^2)/(4-y^4)\]

Answer 2

that's y^2/(2+y^2)(2-y^2) just so you know..you might have an idea afterwards

Answer 3

hey i did this question :P but the thing is i did this again it is converted into partial fraction, so we have to do partial fraction two time, but i wanna do it in a shorter way possible

Answer 4

partial fraction is the only thing i see possible...but why two times???

Answer 5

yehh u do it one time and man u will c u need to do it again

Answer 6

(2-y^2) <---------- is this linear or quadratic in form??

Answer 7

Ay+b(2-y^2) + Cy+D(2+y^2) = y^2

2Ay - Ay^3 + 2B -By^2 + 2Cy + Cy^3 + 2D + Dy^2 = y^2

coeff y^3

-A + C = 0

coeff y^2

-B + D = 1

coeff y
2A + 2C =0

coeff constant

2B + 2D = 0

-2A + 2C = 0
2A + 2C = 0
2C = 0
C = 0

-2b + 2D = 2
2B + 2D = 0
4D = 2
D = 1/2

A = 0
B = -1/2

so...

-1/2(2+y^2) + 1/2(2-y^2)

that's what you got right? that's only one partial fraction