Question

given the transformation u=y-lnx, v=y-x+1 ... calculate partial derivatives: dx/du (v=const) and dy/dv (u=const)

Answer 1

I don't think I understand this one, are we not doing\[u=y-\ln x\]\[x=e^{y-u}\]\[\frac{\partial x}{\partial u}=-e^{y-u}\]?
or do we have to deal with y somehow?

Answer 2

it should be with the jacobians somehow ..