Question

A 200 g particle gains a momentum of 25 Ns in 12 s starting from rest. Find the
kinetic energy of the particle and the applied force.help !

Answer 1

Momentum is given by mass *velocity.
Taking 25/ 0.2 =125m/s

Kinetic energy = 0.5*m *v^2
0.5*0.2*125^2=1562.5J

Applied force = mass * acceleration.
since it took 12 seconds for the particle to go from 0 m/s to 125m/s,
acceleration= 125/12= 10.4m/s^2

Force = 0.2 * 10.4
2.08N

Answer 2

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