Question

anybody wants to help me with eigenvectors?

Answer 1

vectors are the result of the values ....

Answer 2

values are the result of the vectors ...

Answer 3

question number 3.. the eigen value is.. \[\lambda1= 4; \lambda2= -1; \lambda3= -2\]

Answer 4

can we gordon jauss to get vectors?

Answer 5

yes

Answer 6

lol, yes amistre we can, but seems like overkill

Answer 7

:)

Answer 8

(A-Li)x = eugene vector ... maybe

gonna have to look it up again

Answer 9

(A-Li)v = 0

where v is the eugene vector

Answer 10

Fool thinks it's overkill to do Gauss-Jordan, but I don't see another way offhand, so looking at\[(\lambda_1 I-A)=\]which reduces toand so we get\[x_1=-\frac12 t\]\[x_2=0\]\[x_3=t, t\in\mathbb R\]