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Mathematics
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OpenStudy (anonymous):
i to the 12th power?
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OpenStudy (bahrom7893):
go for it saso!
OpenStudy (sasogeek):
\[\large i^{12} \]
OpenStudy (sasogeek):
unless i has a particular value, this is the meaning of your statement :)
OpenStudy (anonymous):
i^12 = 1
OpenStudy (anonymous):
\[i ^{12}=(i ^{4})^{3}\]
\[i ^{4}=i ^{2}*i ^{2}=-1*-1=1\]
\[(i ^{4})^{3}=(1)^{3}=1\]
So your final answer is 1.
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OpenStudy (sasogeek):
\[\large i=\sqrt{-1}? \text{ is it this 'i' the question is referring to?} \]
OpenStudy (anonymous):
I thought so..
OpenStudy (sasogeek):
i see :) I thought 'i' here was just any other variable :P
OpenStudy (anonymous):
Thats how i understood the question lol
OpenStudy (anonymous):
Had no other ideas to it :)
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OpenStudy (sasogeek):
oh well problem solved :D you guys are just amazing!
OpenStudy (anonymous):
Well so are you buddy so are you!
OpenStudy (sasogeek):
aint that cute lol :P i love the people of openstudy, u guys just keep me coming back :)
OpenStudy (anonymous):
Well same here, just the same. Infact it's better than Facebook!
OpenStudy (sasogeek):
heck i spend more time here than fb, i go to fb for notifications, i come here to interact!
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OpenStudy (anonymous):
I actually closed my FB account ever since I came here.
OpenStudy (sasogeek):
oh wow :) impressive! :)
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