i to the 12th power?
go for it saso!
\[\large i^{12} \]
unless i has a particular value, this is the meaning of your statement :)
i^12 = 1
\[i ^{12}=(i ^{4})^{3}\] \[i ^{4}=i ^{2}*i ^{2}=-1*-1=1\] \[(i ^{4})^{3}=(1)^{3}=1\] So your final answer is 1.
\[\large i=\sqrt{-1}? \text{ is it this 'i' the question is referring to?} \]
I thought so..
i see :) I thought 'i' here was just any other variable :P
Thats how i understood the question lol
Had no other ideas to it :)
oh well problem solved :D you guys are just amazing!
Well so are you buddy so are you!
aint that cute lol :P i love the people of openstudy, u guys just keep me coming back :)
Well same here, just the same. Infact it's better than Facebook!
heck i spend more time here than fb, i go to fb for notifications, i come here to interact!
I actually closed my FB account ever since I came here.
oh wow :) impressive! :)
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