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Mathematics 7 Online
OpenStudy (anonymous):

i to the 12th power?

OpenStudy (bahrom7893):

go for it saso!

OpenStudy (sasogeek):

\[\large i^{12} \]

OpenStudy (sasogeek):

unless i has a particular value, this is the meaning of your statement :)

OpenStudy (anonymous):

i^12 = 1

OpenStudy (anonymous):

\[i ^{12}=(i ^{4})^{3}\] \[i ^{4}=i ^{2}*i ^{2}=-1*-1=1\] \[(i ^{4})^{3}=(1)^{3}=1\] So your final answer is 1.

OpenStudy (sasogeek):

\[\large i=\sqrt{-1}? \text{ is it this 'i' the question is referring to?} \]

OpenStudy (anonymous):

I thought so..

OpenStudy (sasogeek):

i see :) I thought 'i' here was just any other variable :P

OpenStudy (anonymous):

Thats how i understood the question lol

OpenStudy (anonymous):

Had no other ideas to it :)

OpenStudy (sasogeek):

oh well problem solved :D you guys are just amazing!

OpenStudy (anonymous):

Well so are you buddy so are you!

OpenStudy (sasogeek):

aint that cute lol :P i love the people of openstudy, u guys just keep me coming back :)

OpenStudy (anonymous):

Well same here, just the same. Infact it's better than Facebook!

OpenStudy (sasogeek):

heck i spend more time here than fb, i go to fb for notifications, i come here to interact!

OpenStudy (anonymous):

I actually closed my FB account ever since I came here.

OpenStudy (sasogeek):

oh wow :) impressive! :)

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