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OpenStudy (anonymous):
A velocity-time graph has been drawn. What does the area below the line represent?
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OpenStudy (anonymous):
For example, I got max t of 1.05s, and velocity reached 1.39m/s, meaning that the area would be 0.73m. What does this represent?
OpenStudy (amistre64):
area is usually a result of integrating the function
OpenStudy (amistre64):
velocity integrates to position
OpenStudy (anonymous):
So what would it exactly mean in my example situation? don't quite get it.. :/
OpenStudy (amistre64):
no to sure; unless it has something to do with the average position across the interval
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OpenStudy (anonymous):
by the way, we're studying motion and acceleration.
experiment using motion cart and the ramp, with tickertape and timer
OpenStudy (amistre64):
yeah, physics applications are still a weak point for me ... id have to read up into what it tends to translate into
OpenStudy (amistre64):
displacement
OpenStudy (anonymous):
displacement? hmm ok! thanks
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OpenStudy (amistre64):
yw, I knew it had something to do with position :)
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