Question

Find the product: -9y^2(y^4+8y^3-3y^2+8y+7)

Answer 1

Multiply -9y^2 with each term inside the parenthesis.

Answer 2

Remembering that coefficients multiply regularly and exponents add when you multiply.

Answer 3

ok kind of lost

Answer 4

If you had \[x^2(x+1)\] you would get \[x^3+x^2\] when you multiplied through. You need to use this process for your problem. All I did was take x^2 and multiplied it by x^1 and then 1.

Answer 5

ok so would it be 9y^6-72y^5+27y^4-72y^3-63y^2

Answer 6

Yes except the first term is also negative.

Answer 7

ok how would you do (x+4)(x^2-4x+16)

Answer 8

The same way except you need to multiply the x throughout the (x^2-4x+16) and then you need to do the same with the 4 and add the result.

Answer 9

So kind of like x(x^2-4x+16) and then add 4(x^2-4x+16).

Answer 10

4x^3-16x^2+64x

Answer 11

Nope...you messed up somewhere.

Answer 12

ok how about x^3-16x+16 is that correct what i did in the last one was multiply and this one I didn't

Answer 13

No.

Answer 14

ok where am i going wrong

Answer 15

\[(x+4)(x^2-4x+16)=x^3-4x^2+16x+4x^2-16x+64\]

Answer 16

It then simplifies, but what I did was take that x and multiply it through the polynomial and then did the same with the 4 and added everything together.