with non uniform circular motion to find the acceleration of R do you do V^2/magnitude of R
what do you mean the acceleration of R ? could you elaborate?
well i want to find the tension of the rope of the pendulum and to do that i have to take ma and im given the mass of the pendulum and length, but not the acceleration
and im given the velocity
does it say at what point it is in the swing?
ya as its swinging upward and it makes a certain angle with the vertical
|dw:1330320345927:dw|all the forces along the r direction must be zero, so let's consider that
yep looks like what i drew
|dw:1330320558563:dw|so along r we have the force of gravity in that direction and the centripetal force being cancelled by tension. Notice that the component of gravity along r will be the cosine of the angle that the string makes with the vertical:\[\large \sum F_r=F_{gr}+F_c-T=mg\cos\theta+m\frac{v^2}r-T=0\]this can be solved for the tension T
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