Question

Please factor this:

-n^2-3n+28/3n^3+9n^2-84n

Answer 1

the first step is to factor out the n. What do you get?

Answer 2

\[-n^2-3n+\frac{28}{3n^3}+9n^2-84n =0\]
multiply this equation by 3n3
\[-3n^5-9n^3+28+27n^5-252n^4 =0\]

Answer 3

Laura .. do complete or i do ?

Answer 4

The whole thing is a fraction, by the way.

Answer 5

\[24 n^5 -252 n^4 -9n^3+28 = zero\]

Answer 6

Everything before the "/" is in the numerator, and everything after it is in the denominator.

Answer 7

The part I don't know how to factor is 3n^3+9n^2-84n, which is in the denominator.

Answer 8

Thank you for helping me with that.