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Mathematics 13 Online
OpenStudy (anonymous):

Integral: (sec x)^4(tanx)^2 dx

OpenStudy (dumbcow):

i would substitute here u = tan x du = sec^2 x dx then sec^2 will cancel leaving sec^2 on top note: sec^2 = 1+tan^2 --> integral u^2(1+u^2) du

OpenStudy (anonymous):

Thanks!

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