Question

HELPP PLEASE
What are the x– and y–intercepts of the quadratic equation y = x2 + 2x – 3?

x–intercepts: (3, 0) and (–1, 0)
y–intercept: (0, 3)








x–intercepts: (3, 0) and (–1, 0)
y–intercept: (0, –3)








x–intercepts: (–3, 0) and (1, 0)
y–intercept: (0, –3)








x–intercepts: (–3, 0) and (1, 0)
y–intercept: (0, 3)

Answer 1

x intercept (1, 0) and ( -3, 0)
y intercept ( 0, -3)

Answer 2

you can get the answer down to 2 possible choices, because the y intercept happens when x=0, Wherever you see x in the equation, replace it with zero. You get
y= 0*0 + 2*0 – 3
you know what 0*0 ! and 2*0, so y= -3 is one of the answers
as an (x,y) pair, it is (0,-3)