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OpenStudy (anonymous):
the length of a rectangle is 6 meters more than its width. if the area is 91 square meters, what is the length and width?
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OpenStudy (anonymous):
this is in regards to quadratic equatons
OpenStudy (anonymous):
l=w+6
w*l=91
w(w+6)=91
w^2+6w-91=0
now solve...
OpenStudy (anonymous):
ok thank u!:)
OpenStudy (anonymous):
yw
OpenStudy (anonymous):
I cant find a common factor for 91 and 6?
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OpenStudy (anonymous):
got it:)
OpenStudy (campbell_st):
if you can't find factors use the general quadratic formula... less stress..
OpenStudy (campbell_st):
but I think its 13 and 7
OpenStudy (campbell_st):
oops 13 and - 7
OpenStudy (anonymous):
yes thank you:) I got (w-7)(w+13)
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OpenStudy (campbell_st):
don't look for common factors.. look for factors of the constant that add to the coefficient of x
OpenStudy (anonymous):
would this be square meters as the units?
OpenStudy (anonymous):
take only the positive value,the unit is meters
OpenStudy (anonymous):
ok thank you:) so, look for factors of the constant that add to the coeffiecent of x :)..gotcha:)
OpenStudy (anonymous):
ok thx:)
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OpenStudy (anonymous):
w ( w +6) -91 = 0
w^2 + 6w - 91 = 0
x = -3 +10 = 7 (omit negative value)
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