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Which is the derivate of:
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Of...
\[y=3\sqrt[3]{x}-(e^2/2)\]
y = 3 x^(1/3) - e^2/2 dy/dx = x^(-2/3) - 0 = 1 / x(2/3) = 1 / cuberoo t(x^20
Yes but why \[e^2/2\] is 0?
e isnt a variable; its a constant
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because its a constant
Ah.. ok, not already done at school but ok! TY BOTH!
yw
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