Question

solve 2x^4+x^2-1

Answer 1

you don't have an equation

Answer 2

=0

Answer 3

u can solve it by replacinf x^2=t and u'll get 2t^2+t-1=0 and now u can solve it like a second grade eq.

Answer 4

use substitution:
\[x^2=t\]\[2t^2+t-1=0\]\[t _{1,2}=(-1\pm \sqrt{9})/4\]\[t _{1,2}=(-1\pm3)/4\]\[t1=1/2\]\[t _{2}=-1\] but you throw away that second solution because it's negative so the solutions are \[x _{1,2}=\pm(1/\sqrt{2})\]

Answer 5

Guys arent we suppose to have 4 solutions?um a bit lost

Answer 6

since we have x^4?

Answer 7

yea u get 4 solutions

Answer 8

I meant you wanted real solutions...:D OK then you can use x^2=-1 so other solutions are i and -i

Answer 9

how guys?

Answer 10

from wht nenad got.....and so on....