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\[x={-1 \over x}\]
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x= i
multiplying by \(x\) on both sides, \(x^2 = -1\) so be definition, \(x=i=\sqrt{-1}\)
so where does the negative sign go?
By definition, \(\sqrt{-1} = i\) and \(i^2 = -1\)
\[\sqrt{-1}={-1 \over \sqrt{-1}}\]
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Yes, it's definitive that -√(i)=i^-1, I thought.
the negative comes from the index?.
i^n=i^nmod(4)
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