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Determine all real values of x given that 6^(x+1)-6^x=3^(x+4)-3^x
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apparently the answer is 4, but i am not sure exactly how. somehow this can be rewritten. let me try with paper
\[6^x(6-1)=3^x(3^4-3)\] maybe that is a good start
then \[5\times 6^x=80\times 3^x\]
\[6^x=16\times 3^x\] \[\frac{6^x}{3^x}=16\] \[2^x=16\] \[x=4\] there i knew it was possible
thanks!
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