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Mathematics 16 Online
OpenStudy (anonymous):

By writing sin3x as sin(x+2x) Show that sin3x=3sinx=4sin^3x

OpenStudy (anonymous):

??

OpenStudy (anonymous):

that ain't right

OpenStudy (anonymous):

It is written like that I'm assuming they mean sin3x=sin3x-4sin^3x But I don't really understand it

OpenStudy (anonymous):

oops sorry it is supposed to be 3sinx-4sin^3x sorry about that

OpenStudy (mimi_x3):

\[\sin3x = 3sinx -4\sin^3x\] Use: \(\sin(2x+x)\) to prove it.

OpenStudy (anonymous):

I just don't know how to start it with sin(2x+x)

OpenStudy (mimi_x3):

Well, expand it first using the formula sin(a+b) \[\sin2xcosx + \cos2xsinx\]

OpenStudy (anonymous):

oh! How dumb of me :( I got it from here, totally forgot about that.

OpenStudy (mimi_x3):

ok, do you need more help? on how to continue it?

OpenStudy (anonymous):

I believe I can figure this question out from here. Thank you so much for jogging my memory!

OpenStudy (mimi_x3):

yw (:

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