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Physics 13 Online
OpenStudy (amistre64):

i think i did this right so far; hard to tell :)

OpenStudy (amistre64):

OpenStudy (amistre64):

i worked alot of it over in math

OpenStudy (amistre64):

i had no idea if using pounds and feet mattered so I tried to convert it into meters and kgs

OpenStudy (amistre64):

4572 meters to start with: 1670.946 felled, if i did it right ---------- 2901.054 more to go, so if i rely upon the displacement idea i get: \[\int_{0}^{x} v(t)\ dt=2901.054\] \[71.1186x-498.798\ exp(-0.1378\ x)+498.798=2901.054\] \[71.1186x-498.798\ exp(-0.1378\ x)-1402.256=0\] when x = 20.1535 so she would have been aloft for about 40 seconds

OpenStudy (amistre64):

only thing left to do is see how the velocity at 20 seconds compares to terminal lol

OpenStudy (anonymous):

So you are talking to yourself? :D

OpenStudy (anonymous):

Let me finish up this homework of mine real fast then I'll take a stab at it.

OpenStudy (amistre64):

:) i do talk to myself

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