Question

2(6(2/5)+7(1/3) )
i have the decimal answer but im supposed to present answer as a mixed number, integer, or proper fraction and my mind is shutting down lol

Answer 1

2 [ 6 (2/5) + 7 (1/3) ] --> Is this the problem? My eyes are shutting down.

Answer 2

yes lol

Answer 3

the numbers in parenthesis are mixed number fractions

Answer 4

What is your decimal answer? I want to see if my fractional answer is anywhere near it.

Answer 5

rounded its 9.5 but i could be wrong

Answer 6

Are you saying that this --> 7 (1/3) is a mixed number?

Answer 7

yes and the 6(2/5) is one also

Answer 8

Now, a mixed number is something like 2 and 3/4 which is written as 2 3/4 with no multiplication symbol or grouping symbol. 2 3/4 = 11/4 as an improper fraction.

What is odd is that my fractional answer is close to your decimal answer but I did not see any mixed numbers.

Answer 9

yea the equation here is written right but i judt didnt know how to type it right on here sorry its 2(6 2/5+7 1/3)

Answer 10

The problem is then:

2 [ 6 2/5 + 7 1/3 ] . In your book, are their parentheses around the 2/3 and the 1/3 ?

Answer 11

nope

Answer 12

Okay. Now worries but I need to recalculate.

What is 6 2/5 as an improper (top heavy) fraction? Ditto for 7 1/3.

Answer 13

2 [ 6 2/5 + 7 1/3 ] =

2 [ 32/5 + 22/3 ] = (agree so far?)

Answer 14

yes

Answer 15

2 [ 32/5 + 22/3 ] =

Distributive property time so

2 [ 32/5 ] + 2 [ 22/3] =

Answer 16

2 [ 32/5 ] + 2 [ 22/3] =

64/5 + 44/3 = ---> Agree?

Answer 17

192/15 + 220/15 = 412/15 -- improper fraction

= 9 7/15 as mixed number (no parenthesis) --------> I think this is the one. Check.

= 27.47 approx

Answer 18

9 7/15 as in 9 and seven-fifteenths

Answer 19

Strange that this rounds to 9.5 but you were doing mixed numbers from the start.