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solve the integration f(sinx+cosx)^2dx
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is this \[\int(\sin(x)+\cos(x))^2dx\]?
yes
square and get \[\sin^2(x)+\cos^2(x)+2\sin(x)\cos(x)=1+\sin(2x)\] then it should be ok
\[\int 1dx+\int\sin(2x)dx\]
can u tell me easy method to sove like this integrations?
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not sure what you mean. the original integral wants you to square.
ok
if you mean how to solve \[\int\sin(2x)dx\] you visualize what you would get if you take the derivative of \[\cos(2x)\] you would get \[-2\sin(2x)\] but you want just \[\sin(2x)\] so your integral is \[-\frac{1}{2}\cos(2x)\]
ok ok
thanks my dear
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\[\int\limits_{\sec^2xcosec^2x}^{dx}\]
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