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Chemistry 14 Online
OpenStudy (anonymous):

A concentration cell consists of two Sn/Sn2+ half-cells. The solution in one half-cell A is 0.13 M Sn(NO3)2 and is 0.87 M Sn(NO3)2 in the other half-cell B. Calculate the cell potential at 25oC.

OpenStudy (anonymous):

E=-0.059/2 log 0.13/0.87. (From nernst equation Eo=0 as both electrodes are same/

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