A man of weight W is standing on a lift which is moving upward with an acceleration a. The apparent wieght of the man is

Question

anonymous · Answer

See, I think the new weight would be:
W1 = m(g + a) = mg + ma = W + ma = W + (W/g)a
Please confirm with other experts also.

anonymous · Answer

Yes your answer is right

anonymous · Answer

Can you explain it in much more detail?

anonymous · Answer

Thanks Yaar.

anonymous · Answer

How you got m(g+a)?

anonymous · Answer

see, when the object is moving upward, always add the acceleration due to gravity and the new acceleration. Multiply the sum by mass of the object. U will get the force acting on it.

anonymous · Answer

The force acting on it would be the aapparent wieght of man?

anonymous · Answer

apparent

anonymous · Answer

Will it be the apparent weight of man?

anonymous · Answer

I think most probably it should be.

anonymous · Answer

Ok, Thanks a lot

anonymous · Answer

U r welcome.

anonymous · Answer

yes u have given the right formula but how?
here it is
when the lift is moving up,
the normal force is graeter than the weight of man mg
but apparent weight or weight in general of a body is determined by the NORMAL FORCE/NORMAL REACTION
hence here 
N-mg=ma
N=mg+ma
again i repeat when we say the WEIGHT OF A BODY IS SOMETHING IT IS ACTUALLY THE NORMAL REACTION/FORCE AND NOT mg of the body